tests: Simplify origin comparison and improve pytest diff on failure
By using a single equality instead of checking len() then zip() to check one by one, pytest can find the common/missing elements and print them nicely when the two lists are unequal.
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8 changed files with 53 additions and 94 deletions
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@ -1373,28 +1373,22 @@ def test_arch_lister(datadir, requests_mock_datadir, swh_scheduler):
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assert res.pages == 9
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assert res.origins == 12
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expected_origins_sorted = sorted(expected_origins, key=lambda x: x.get("url"))
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scheduler_origins_sorted = sorted(
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swh_scheduler.get_listed_origins(lister.lister_obj.id).results,
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key=lambda x: x.url,
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)
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assert len(scheduler_origins_sorted) == len(expected_origins_sorted)
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scheduler_origins = swh_scheduler.get_listed_origins(lister.lister_obj.id).results
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assert [
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(
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scheduled.visit_type,
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scheduled.url,
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scheduled.extra_loader_arguments.get("artifacts"),
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scheduled.extra_loader_arguments.get("arch_metadata"),
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scheduled.extra_loader_arguments["artifacts"],
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scheduled.extra_loader_arguments["arch_metadata"],
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)
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for scheduled in scheduler_origins_sorted
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for scheduled in sorted(scheduler_origins, key=lambda scheduled: scheduled.url)
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] == [
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(
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"arch",
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expected.get("url"),
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expected.get("extra_loader_arguments").get("artifacts"),
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expected.get("extra_loader_arguments").get("arch_metadata"),
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expected["url"],
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expected["extra_loader_arguments"]["artifacts"],
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expected["extra_loader_arguments"]["arch_metadata"],
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)
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for expected in expected_origins_sorted
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for expected in sorted(expected_origins, key=lambda expected: expected["url"])
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]
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